Differences

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--- public:calculator:guides:dm41x_ppc [24/01/26 12:21 GMT] – [example] john
+++ public:calculator:guides:dm41x_ppc [24/01/26 12:38 GMT] (current) – [Solve (SV)] john
@@ Line 6: / Line 6: @@
 ** Various useful functions from the PPC ROM **
+  * PPC Manual from here : [[https://literature.hpcalc.org/items/1330]]
 ===== Solve (SV) =====
-Similar to other Solvers (e.g. the Advantage Pac [[dm41x_solve|]] but with some minor differences to be aware of.
+Similar to other Solvers (e.g. the Advantage Pac [[dm41x_solve|Solve]]) but with some minor differences to be aware of.
-  * Put the name of the program containing the expression to be solved in register 6
+  * Put the Global Label (name) of the program (in this example it's ''LBL AA'') containing the expression to be solved in register 6
     * <key>ALPHA</key>AA<key>ALPHA</key>
-    * ASTO 06
+    * <key>XEQ</key><key>ALPHA</key>''ASTO''<key>ALPHA</key>''06''
-  * The program with the expression to be solved must be written as though ''x'' is on the x-stack only
+  * The program with the expression to be solved must be written as though unknown ''x'' is on the x-stack only
-    * other solvers "fill the stack" with X
+    * other solvers "fill the stack" with ''x''
-    * here you need to manipulate the stack - easiest is to just ''ENTER'' ''ENTER'' ''ENTER'' and then treat the same as other solvers, and use ''x<>y'' to pull a fresh copy of X as needed
+    * here you need to manipulate the stack to get ''x'' as needed. It's easiest is to just ''ENTER'' ''ENTER'' ''ENTER'' and then treat the stack the same as other solvers (i.e. as if it's filled with ''x'' and you use ''x<>y'' to pull a fresh copy of ''x'' as needed in the expression).
-  * Put a "step size" in y and a "start value" in x
+  * Put a "step size" in y and a "start value" in x (e.g. ''-3'')
-    * 0 ENTER 3
+    * ''0'' <key>ENTER</key> ''-3''
   * run ''SV''
@@ Line 43: / Line 44: @@
 </code>
+=== for the first root ===
   * ''0'' <key>ENTER</key> ''1''
@@ Line 49: / Line 52: @@
 and the answer comes.....
-.850781059
+''0.850781059''
-  * for the other root
+=== for the second root ===
   * ''0'' <key>ENTER</key> ''-3''
   * <key>XEQ</key><key>ALPHA</key> ''SV'' <key>ALPHA</key>
@@ Line 57: / Line 61: @@
 and the answer comes.....
-  -2.50781060
+''-2.350781060''
-===== Section Two =====
@@ Line 71: / Line 74: @@
-{{tag>}}
+{{tag>calculator dm41x}}